Add day3 part2
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@ -6,13 +6,24 @@ use std::collections::HashSet;
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use std::fs::File;
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use std::io::{BufRead, BufReader};
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// Map a character (indicating an "item") to its "priority".
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fn char_to_prio(c: char) -> u32 {
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// Fortunately we can cast all chars to u32, which makes this a matter of some simple
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// arithmetic.
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match c {
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'a'..='z' => c as u32 - 'a' as u32 + 1,
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'A'..='Z' => c as u32 - 'A' as u32 + 27,
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_ => panic!("Got non-ascii alphabetic char!"),
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}
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}
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fn main() -> StdError<()> {
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// Open the input file and split all the lines.
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let lines: Vec<_> = BufReader::new(File::open("input/day3.txt")?)
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.lines()
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.collect::<Result<_, _>>()?; // "Short circuit" any Errors in the iterator
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let sum: u32 = lines
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let part1: u32 = lines
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.iter()
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.map(|l| {
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assert!(l.len() % 2 == 0); // We won't be able to evenly split a odd-length line!
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@ -22,17 +33,35 @@ fn main() -> StdError<()> {
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HashSet::<char>::from_iter(one.chars())
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// ... then calculate the intersection, giving us the "items" (chars) in common
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.intersection(&HashSet::from_iter(two.chars()))
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.map(|c| match c {
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// Now, we map our "items" to their "priorities".
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// Fortunately we can cast all chars to u32, which makes this a matter of some
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// simple arithmetic.
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'a'..='z' => (*c as u32) - 'a' as u32 + 1,
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'A'..='Z' => (*c as u32) - 'A' as u32 + 27,
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_ => panic!("Got non-ascii alphabetic char!"),
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})
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.map(|c| char_to_prio(*c))
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.sum::<u32>() // Sum the priorities of items in common in each "rucksack"
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})
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.sum(); // Sum all the rucksacks' priorities
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println!("Part 1: {}", sum);
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println!("Part 1: {}", part1);
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let part2: u32 = lines
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// First, map our lines to hashsets of their chars
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.iter()
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.map(|l| HashSet::from_iter(l.chars()))
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.collect::<Vec<_>>()
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// Then split them into chunks of 3
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.chunks(3)
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.map(|c: &[HashSet<_>]| {
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// And reduce each chunk of 3 into a single intersection of chars...
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let common: Vec<char> = c
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.into_iter()
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.cloned()
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.reduce(|acc, s| acc.intersection(&s).cloned().collect())
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.unwrap()
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.into_iter()
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.collect();
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// ... which should only be one!
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assert!(common.len() == 1);
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common[0]
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})
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.map(char_to_prio)
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.sum();
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println!("Part 2: {}", part2);
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Ok(())
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}
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